The zeroes of the polynomial f x - x 2-3 isA- 3-3 B- -3- -3- 2-2D- 0

The correct option is B √(3),√(3)For zeroes of polynomial f(x) = 0 ⇒ x^2 3 = 0 ⇒ nbsp;(x √(3))(x+√(3)) = 0 ∴ x = ±√(3) Therefore, the zeroes are √(3) and √ ...

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Standard XII

Mathematics

Quadratic Polynomial

The zeroes of...

Question

The zeroes of the polynomial $f (x) = x^{2} - 3$ is

3, - 3

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2, - 2

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- \sqrt{3}, \sqrt{3}

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Solution

The correct option is C $- \sqrt{3}, \sqrt{3}$
For zeroes of polynomial
$f (x) = 0 \Rightarrow x^{2} - 3 = 0 \Rightarrow (x - \sqrt{3}) (x + \sqrt{3}) = 0 ∴ x = \pm \sqrt{3}$
Therefore, the zeroes are $- \sqrt{3}$ and $\sqrt{3}$

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Quadratic Polynomial

Standard XII Mathematics

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The zeroes of the polynomial f(x)=x2−3 is

The correct option is C −√3,√3For zeroes of polynomial f(x)=0⇒x2−3=0⇒(x−√3)(x+√3)=0∴x=±√3 Therefore, the zeroes are −√3 and √3

The zeroes of the polynomial $f (x) = x^{2} - 3$ is

The correct option is C $- \sqrt{3}, \sqrt{3}$
For zeroes of polynomial
$f (x) = 0 \Rightarrow x^{2} - 3 = 0 \Rightarrow (x - \sqrt{3}) (x + \sqrt{3}) = 0 ∴ x = \pm \sqrt{3}$
Therefore, the zeroes are $- \sqrt{3}$ and $\sqrt{3}$