Question

The zeroes of the polynomial $f\left(x\right)=x^2-3$ is

• A. $3,-3$
• B. $2,-2$
• C. $-\sqrt{3},\sqrt{3}$
• D. $0$

Answer 1

The correct option is C $-\sqrt{3},\sqrt{3}$

For zeroes of polynomial
$f\left(x\right)=0\Rightarrow x^2-3=0\Rightarrow (x-\sqrt{3})(x+\sqrt{3})=0\therefore x=\pm \sqrt{3}$
Therefore, the zeroes are $-\sqrt{3}$ and $\sqrt{3}$