The zeroes of the polynomial P(x)=ax2+bx+c are 1 and 2. Find the value of a, b and c.
a = 1, b = -3 , c = 1
a = 1 , b = -3, c = 2
a = 3, b = -1, c = 1
a = -1 , b = -3, c = -2
Given the zeroes of P(x) are 1 and 2. ⟹P(x)=(x−1)(x−2) ⟹ax2+bx+c=x2−3x+2 ⟹a=1, b=−3, and c=2
If 10800=2a × 3b × 5c then find the value of a, b and c.
Let f(x)=ax2+bx+c. Then, match the following. a. Sum of roots of f(x) = 01.–bab. Product of roots of f(x) = 02.cac. Roots of f(x) = 0 are real and distinct3.b2–4ac=0d. Roots of f(x) = 0 are real and identical.4.b2–4ac>0