The zeroes of the polynomial p x - x -22- x -22 isA- 1B- XC- 0D- 2

The correct option is C 0p(x)=(x 2)^2 (x+2)^2 For zeroes of polynomial, put p(x)=0 (x 2)^2 (x+2)^2=0 nbsp;[a^2 b^2=(a b)(a+b)] (x 2+x+2)(x 2 x 2)=0 nbsp; ...

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Standard IX

Mathematics

Factor of Polynomials

The zeroes of...

Question

The zeroes of the polynomial $p (x) = (x - 2)^{2} - (x + 2)^{2}$ is ____.

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0.0

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Solution

The correct option is C 0.0
$p (x) = (x - 2)^{2} - (x + 2)^{2}$
For zeroes of polynomial, put $p (x) = 0$
$(x - 2)^{2} - (x + 2)^{2} = 0$
$[a^{2} - b^{2} = (a - b) (a + b)]$
$(x - 2 + x + 2) (x - 2 - x - 2) = 0$
$2 x (- 4) = 0$
$- 8 x = 0$
$x = 0$
Hence, the zero of polynomial is 0.

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The zeroes of the polynomial p(x)=(x−2)2−(x+2)2 is ____.

The correct option is C 0.0p(x)=(x−2)2−(x+2)2 For zeroes of polynomial, put p(x)=0 (x−2)2−(x+2)2=0 [a2−b2=(a−b)(a+b)] (x−2+x+2)(x−2−x−2)=0 2x(−4)=0 −8x=0 x=0 Hence, the zero of polynomial is 0.

The zeroes of the polynomial $p (x) = (x - 2)^{2} - (x + 2)^{2}$ is ____.

The correct option is C 0.0
$p (x) = (x - 2)^{2} - (x + 2)^{2}$
For zeroes of polynomial, put $p (x) = 0$
$(x - 2)^{2} - (x + 2)^{2} = 0$
$[a^{2} - b^{2} = (a - b) (a + b)]$
$(x - 2 + x + 2) (x - 2 - x - 2) = 0$
$2 x (- 4) = 0$
$- 8 x = 0$
$x = 0$
Hence, the zero of polynomial is 0.