The zeroes of the polynomial x 2- x -12 areA- 3-4B- -3-4C- 3-4D- 2-6

The correct option is B 3, 4 p(x)=0 ⇒ x^2 x 12=0 nbsp;x^2+3x 4x 12=0 ......(splitting the middle term) x(x+3) 4(x+3)=0 (x+3)(x 4)=0 x+3=0 ,(x 4)=0 ⇒ x= 3 ...

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Standard X

Mathematics

Roots of Quadratic Equation

The zeroes of...

Question

The zeroes of the polynomial $x^{2} - x - 12$ are _, __.

3, 4

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3, - 4

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- 3, 4

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2, 6

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Solution

The correct option is C $- 3, 4$
$p (x) = 0 \Rightarrow x^{2} - x - 12 = 0$
$x^{2} + 3 x - 4 x - 12 = 0$ ......(splitting the middle term)
$x (x + 3) - 4 (x + 3) = 0$
$(x + 3) (x - 4) = 0$
$x + 3 = 0, (x - 4) = 0$
$\Rightarrow x = - 3, 4$

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The zeroes of the polynomial x2−x−12 are ___, ____.

The correct option is C −3,4 p(x)=0⇒x2−x−12=0 x2+3x−4x−12=0 ......(splitting the middle term) x(x+3)−4(x+3)=0 (x+3)(x−4)=0 x+3=0,(x−4)=0 ⇒x=−3,4

The zeroes of the polynomial $x^{2} - x - 12$ are _, __.

The correct option is C $- 3, 4$
$p (x) = 0 \Rightarrow x^{2} - x - 12 = 0$
$x^{2} + 3 x - 4 x - 12 = 0$ ......(splitting the middle term)
$x (x + 3) - 4 (x + 3) = 0$
$(x + 3) (x - 4) = 0$
$x + 3 = 0, (x - 4) = 0$
$\Rightarrow x = - 3, 4$