The zeroes of the polynomial $x^{2} - x - 12$ are -3 and .

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-3

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-4

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Solution

The correct option is A 4
In order to find the zeros of the polynomial, we equate the polymomial to zero.
$\Rightarrow$ $x^{2} - x - 12 = 0$
$\Rightarrow$ $x^{2} + 3 x - 4 x - 12 = 0$
$\Rightarrow$ $x (x + 3) - 4 (x + 3) = 0$
$\Rightarrow$ $(x + 3) (x - 4) = 0$
$\Rightarrow$ $x + 3 = 0, (x - 4) = 0$
$\Rightarrow x = - 3, 4$ .

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