Question

Then,
Answer: DC produced bisects BC at right angle.
If true then enter 1 else if False enter 0

Answer 1

Let $△ABC$ be an isosceles.

$AB=AC⟶\left(1\right)$

Hence $△DBC$ is isosceles,

$DB=DC⟶\left(2\right)$

In $△ABD$ and $△DBC,AB=AC\text{[From (1)]},BD=DC\text{(From (2))}AD=AD\text{(common)}$

$therefore△ABD\cong △ACD\text{(SSS congruence rule.)}$

The statement is false.