Question

Then eccentricity of the Ellipse $4x^2+y^2-8x-2y+1$ = 0

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

$4x^2+y^2-8x-2y+1=0$
$4(x^2-2x)+(y-1{)}^2=04(x-1{)}^2+(y-1{)}^2=4(x-1{)}^2+\frac{(y-1{)}^2}{4}=1\frac{1}{4}=1-e^2{e}^2=1=\frac{1}{4}e=\sqrt{\frac{3}{2}}$