-1-cos-tan -1-cos-x- then sin x is equal to

The correct option is C tan2(∝/2)Given, ...

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then sin x is equal to

tan²(∝/2)

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cos²(∝/2)

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tan∝

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cot(∝/2)

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{cot}^{- 1} {\sqrt{cos} α} - {tan}^{- 1} {\sqrt{cos} α} = x

sin x

c o t^{- 1} (\sqrt{c o s α}) - t a n^{- 1} (\sqrt{c o s α}) = x

c o t^{- 1} \sqrt{c o s α} - t a n^{- 1} \sqrt{c o s α} = x

π < α < \frac{3 π}{2}

\sqrt{\frac{1 - cos α}{1 + cos α}} + \sqrt{\frac{1 + cos α}{1 - cos α}}

x = \frac{2 sin α}{1 + cos α + sin α}

\frac{1 - cos α + sin α}{1 + sin α}

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