Then the energy dissipated in the circuit in $20 m i n$ is:

960 J

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900 J

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250 J

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500 J

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Solution

The correct option is A $960 J$
$ω = 314 r a d / s$
$V_{r m s} = \frac{10}{\sqrt{2}} V$
$I_{r m s} = \frac{V_{r m s}}{\sqrt{R^{2} + {(X_{L} - X_{C})}^{2}}} = 0.126 A$
Power developed in circuit = $I_{r m s}^{2} R W$

Energy dissipated in 20 mins $= {0.126}^{2} \times 50 \times 20 \times 60 = 952.8 J$
$e n e r g y \approx 960 J$

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Then the energy dissipated in the circuit in 20 min is:

The correct option is A 960 Jω=314rad/sVrms=10√2VIrms=Vrms√R2+(XL−XC)2=0.126APower developed in circuit = I2rmsRWEnergy dissipated in 20 mins =0.1262×50×20×60=952.8J energy≈960J

Then the energy dissipated in the circuit in $20 m i n$ is: