There are 10 balls numbered from 1 to 10 in a box. If one of them is selected at random, what is the probability that the number printed on the ball would be an odd number greater than 4?
A
0.50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.60
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.30
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D0.30 Given: Total number of balls, n(S)=10
To find: the probability that the number printed on the ball would be an odd number greater than 4
Sol: Odd numbers greater than 4 from 1 to 10 are 5,7,9, n(E)=3
Hence, the probability that the number printed on the ball would be an odd number greater than 4=310=0.30