Question

There are 10 cards numbered from 1 to 10. A card is drawn randomly. The probability of getting
an even numbered card is

(a) $\frac{1}{10}$ (b) $\frac{1}{5}$ (c) $\frac{1}{2}$ (d) $\frac{2}{5}$

Answer 1

The number on the cards are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
The even numbers on the cards are 2, 4, 6, 8, 10.
∴ Probability of getting an even numbered card = $\frac{\mathrm{Number}\mathrm{of}\mathrm{even}\mathrm{numbered}\mathrm{card}}{\mathrm{Number}\mathrm{of}\mathrm{cards}\mathrm{with}\mathrm{numbers}\mathrm{from}1\mathrm{to}10}$

$=\frac{5}{10}=\frac{1}{2}$
Hence, the correct option is (c).