wiz-icon
MyQuestionIcon
MyQuestionIcon
11
You visited us 11 times! Enjoying our articles? Unlock Full Access!
Question

There are 10 compartments in passenger train which carries on an average 20 passengers per compartment. If at least 12 passengers were sitting in each compartment and no two compartments have an equal number of passengers then maximum how many passengers can be accommodated in any compartment :

A
64
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
45
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
56
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 56
Total number of passengers = 10 × 20 = 200
In the 9 compartments, the total number of passangers
= 144 (= 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20)
So the no. of passengers in the 10th coach = 200 - 144 = 56

flag
Suggest Corrections
thumbs-up
7
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Averages
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon