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There are 10 compartments in passenger train which carries on an average 20 passengers per compartment. If at least 12 passengers were sitting in each compartment and no two compartments have an equal number of passengers then maximum how many passengers can be accommodated in any compartment :

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Solution

The correct option is C 56
Total number of passengers = 10 $\times$ 20 = 200
In the 9 compartments, the total number of passangers
= 144 (= 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20)
So the no. of passengers in the $10^{t h}$ coach = 200 - 144 = 56

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There are 10 compartments in passenger train which carries on an average 20 passengers per compartment. If at least 12 passengers were sitting in each compartment and no two compartments have an equal number of passengers then maximum how many passengers can be accommodated in any compartment :

The correct option is C 56Total number of passengers = 10 × 20 = 200 In the 9 compartments, the total number of passangers = 144 (= 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20) So the no. of passengers in the 10th coach = 200 - 144 = 56

The correct option is C 56
Total number of passengers = 10 $\times$ 20 = 200
In the 9 compartments, the total number of passangers
= 144 (= 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20)
So the no. of passengers in the $10^{t h}$ coach = 200 - 144 = 56