Question

There are 10 marbles in a box which are marked with the distinct numbers from 1 to 10.
A marble is drawn randomly. The probability of getting prime numbered marble is

(a) $\frac{1}{2}$ (b) $\frac{2}{5}$ (c) $\frac{9}{3}$ (d) $\frac{3}{10}$

Answer 1

The numbers marked on the marbles are 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.
Here, the prime numbers (favourable outcomes) are 2, 3, 5, and 7.
∴ Number of favourable outcomes = 4
Therefore
Probability of getting prime numbered marble = $\frac{4}{10}=\frac{2}{5}$
Hence, the correct option is (b).