Question

There are 10 neutrons in the nucleus of the element ${}_Z{M}^{19}$. It belongs to:

• A. f-block
• B. s-block
• C. d-block
• D. None of these

Answer 1

The correct option is D None of these

${}_Z{M}^{19}$

Mass number = 19

No of neutrons = 10

No. of proton = Atomic number

Mass number = No of proton + No of neutron

$\therefore$ No of proton $=19-10=9$

The element with atomic number 9 is fluorine.

Electronic configuration = $1s^{2}2s^{2}2p^5$

The last electron goes to 2p orbital.

Hence, it is a p-block element.