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Question

There are 10 points in a plane, out of these 6 are collinear. If N is the number of triangles formed by joining these points, then

A
N>190
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B
N100
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C
100<N140
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D
140<N190
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Solution

The correct option is B N100
There are 4 isolated points and 6 collinear points. Hence,

Hence, to form a triangle we need 3 points

Total no of ways we can form the triangle is - 10C3

But we have selected those points also which are collinear.Hence,

Total no of ways = 10C36C3=12020=100

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