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Question

There are 100 turns in a circular coil of a wire, the radius of each is 8.0cm and in this 0.40A current is flowing. What will be the magnitude of the magnetic field at the centre of the coil?

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Solution

Number of turns in coil N=100
Radius R=8.0cm=8×102m
Flowing current I=0.40A
Magnetic field at the centre of coil
B=μ0NI2r
B=4π×107×100×0.402×8×102
B=3.1×104T

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