Question

There are 120 boys and 114 girls in class X of a school. Principal of the school decided as a policy matter to have maximum number of mixed sections, each section has to accommodate equal number of boys and equal number of girls. What is the maximum number of such sections?

Answer 1

Let '$x$' be the total number of sections.

'$y$' is the number of boys in a section.

'$z$' is the number of girls in a section.

Now 120 = $x\times y$

114 = $x\times z$

Dividing both the equations we get:-

$\frac{20}{19}=\frac{y}{z}$

This means that we can let 'y' be equal to 20 and 'z' be equal to 19 (in lowest fraction)

Hence we get:

$x=\frac{120}{20}=6$

Thus there are total $6$ sections.