There are 13 players of cricket out of which 4 are bowlers. In how many ways a team of eleven selected from them so as to include at least two bowlers-

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None of these

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Solution

The correct option is A 78
$78$

Total - no bowlers + 1 bowler = atleast 2

$^{13} C_{11} -^{9} C_{11} + (^{4} C_{11} \times^{9} C_{10}))$

atleast 2

$=^{13} C_{11} - 0 + 0$

$= \frac{13 \times 12}{2 \times 1}$

$= 78$

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There are 13 players of cricket out of which 4 are bowlers. In how many ways a team of eleven selected from them so as to include at least two bowlers-

The correct option is A 7878Total - no bowlers + 1 bowler = atleast 213C11−9C11+(4C11×9C10))atleast 2=13C11−0+0=13×122×1=78

The correct option is A 78
$78$

Total - no bowlers + 1 bowler = atleast 2

$^{13} C_{11} -^{9} C_{11} + (^{4} C_{11} \times^{9} C_{10}))$

atleast 2

$=^{13} C_{11} - 0 + 0$

$= \frac{13 \times 12}{2 \times 1}$

$= 78$