Question

There are 156,208 and 260 students in groups A,B and C respectively. Buses are to be hired for their picnic. Find the minimum number of buses to be hired if same numbers of students are accommodated in each bus.

Answer 1

You should take H.C.F. of 156, 208 and 260.


=> HCF of 156 and 208

P.F. of 156 = 2×2×3×13
P.F. of 208 = 2×2×2×2×13
Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52


=> Now , H.C.F. of 52 and 260

P.F. of 52 = 2×2×13
P.F. of 260 = 2×2×5×13
H.C.F. = 2×2×13 = 52

●Max. number of students per bus = 52

●Total number of students = 156+208+260 = 624 students.

●No. of buses = 624/52 = 12 buses.