Question

There are $180$ members of a committee, In a meeting, $\frac{3}{5}$ of them were present. How many members were absent ?

Answer 1

Total no.of members in committee= 180

$\frac{3}{5}$ of term are present

i.e., $\frac{3}{5}\left(36\right)=108$

No of members absent= 180-108=72