There are 2 bags, which has a total of 50 red balls and 50 blue balls. Each bag has an equal probability of being picked. What is the maximum probability of drawing a red ball, if there are no restrictions on the number of balls that can be put into a bag?

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Solution

The correct option is B

Probability of picking a red ball is maximum when 1 red ball is put in 1 bag and 49 red balls are put in another bag along with the 50 blue balls.

$M a x i m u m p r o b a b i l i t y = \frac{1}{2} \times \frac{49}{99} + \frac{1}{2} \times 1 = \frac{74}{99}$

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There are 2 bags, which has a total of 50 red balls and 50 blue balls. Each bag has an equal probability of being picked. What is the maximum probability of drawing a red ball, if there are no restrictions on the number of balls that can be put into a bag?

The correct option is B Probability of picking a red ball is maximum when 1 red ball is put in 1 bag and 49 red balls are put in another bag along with the 50 blue balls. Maximum probability=12×4999+12×1=7499

The correct option is B

Probability of picking a red ball is maximum when 1 red ball is put in 1 bag and 49 red balls are put in another bag along with the 50 blue balls.

$M a x i m u m p r o b a b i l i t y = \frac{1}{2} \times \frac{49}{99} + \frac{1}{2} \times 1 = \frac{74}{99}$