Question

There are 2 baskets with n identical balls. Half the balls from basket 1 are put into basket 2. The ratio of balls in Basket 1 to Basket 2 gets reversed. Next ${\frac{1}{3}}^{rd}$ and ${\frac{2}{3}}^{rd}$ of the balls from the $1^{st}$ basket and $2^{nd}$ basket respectively are exchanged. The ratio of balls in basket 2 to basket1 is?

• A. 3:1
• B. 2:1
• C. 1:1
• D. 1:2

Answer 1

The correct option is D 1:2

Option (d)

$=\frac{\frac{2}{3}b+\frac{2}{3}a}{\frac{1}{3}b+\frac{1}{3}a}=2:1$

Required ratio(basket 2: basket 1) = 1:2