There are 2 brothers A and B. Probability that A will pass in exam is 3/5 and that B will pass in exam is 5/8. What will be the probability that only one will pass in the exam?

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Solution

Probabliy that A will Pass = $\frac{3}{5}$
Probabliy that B will Pass = $\frac{5}{8}$
Probabliy that A will Fail = $\frac{2}{5}$
Probabliy that B will Fail = $\frac{3}{8}$
Probablilty that only one will pass = P(A $\to$ Pass)P(B $\to$ Fail)+P(B $\to$ Pass)P(A $\to$ Fail)= $\frac{19}{40}$

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There are 2 brothers A and B. Probability that A will pass in exam is 3/5 and that B will pass in exam is 5/8. What will be the probability that only one will pass in the exam?

Probabliy that A will Pass = 35Probabliy that B will Pass = 58Probabliy that A will Fail = 25Probabliy that B will Fail = 38Probablilty that only one will pass = P(A→Pass)P(B→Fail)+P(B→Pass)P(A→Fail)=1940

Probabliy that A will Pass = $\frac{3}{5}$
Probabliy that B will Pass = $\frac{5}{8}$
Probabliy that A will Fail = $\frac{2}{5}$
Probabliy that B will Fail = $\frac{3}{8}$
Probablilty that only one will pass = P(A $\to$ Pass)P(B $\to$ Fail)+P(B $\to$ Pass)P(A $\to$ Fail)= $\frac{19}{40}$