Question

There are 2 buses, Bus A took $2\frac{1}{4}$ hours to reach the destination while Bus B took $2\frac{3}{4}$ hours to reach the same destination. If they both started from same point and followed the same path, how much more time does Bus B take than Bus A to reach the destination?

• A. 40 minutes
• B. 50 minutes
• C. 60 minutes
• D. 30 minutes

Answer 1

The correct option is D 30 minutes

Time taken by Bus A
= $2\frac{1}{4}$ hours
= 2 + $\frac{1}{4}$
= 2 hours + $\frac{1}{4}$ hours

Similarly,

Time taken by Bus B
= 2 hours + $\frac{3}{4}$ hours

Difference in time taken
= 2 hours + $\frac{3}{4}$ hours - 2 hours + $\frac{1}{4}$ hours
= $\frac{3}{4}$ hours - $\frac{1}{4}$ hours

= Three - Quarters - a Quarter
= a half
= $\frac{1}{2}$of an hour
= 30 minutes

Bus B takes 30 minutes more than Bus A to reach the destination.