Question

There are 2 men X and Y who were born in the same year. If X's date of birth is on ${19}^{th}$December 1990, how many dates are possible for Y to be born such that he doesn't have the same birthday as X?

• A. 364
• B. 360
• C. 365
• D. 300

Answer 1

The correct option is A

364

1990 is not a leap year. Hence there are 365 days in the year.

If X's birthday is any one particular day, other than this day there are 364 days (i.e. 365 - 1) left in the year.

Now, Y can be born in any one of these 364 days for not having his and X's birthdays on the same day.