Question

There are 2 numbers such that the sum of twice the first number and thrice the second number is 100 and the sum of thrice the first number and twice the second number is 120. Which is the larger number?

• A. 32
• B. 12
• C. 14
• D. 35
• E. None of these

Answer 1

The correct option is A 32

2x + 3y = 100 ..... (1)
3x + 2y = 120 ..... (2)
Multiply by 3 in Equation (1) and multiply by 2 in Equation (2) and then subtract
$6x+9y=300$
$6x+4y=240$
$\underset{–}{---}$
$5y=60$
$y=12$
$x=32$