Question

There are $2$ red balls and $3$ blue balls and $5$ green balls in a bag. If a ball is drawn at a time, find the probability that it is neither red nor green ball.

• A. $\frac{2}{10}$
• B. $\frac{2}{5}$
• C. $\frac{3}{5}$
• D. $\frac{3}{10}$

Answer 1

The correct option is D $\frac{3}{10}$

Total number of balls $=2+3+5=10$

Number of balls other than red and green ball $=3$

$P\left(A\right)=\frac{Numberoffavorableoutcomes}{TotalNumberofpossibleoutcomes}$

$\therefore P\left(A\right)=\frac{3}{10}$