There are 20 cards numbered from 1 to 20. Krishna selects a card at random from these cards. What is the probability that this card selected at random is a multiple of 3?

$\frac{3}{20}$

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$\frac{7}{20}$

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$\frac{1}{2}$

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$\frac{3}{10}$

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Solution

The correct option is D
$\frac{3}{10}$

The multiples of 3 from 1 to 20 are : 3, 6, 9, 12, 15, and 18. It can be seen that there are 6 multiples.
Number of favourable outcomes = 6
Total number of outcomes = Total number of cards = 20
Hence P(selecting a card divisible by 3) = $\frac{6}{20}$ = $\frac{3}{10}$

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There are 20 cards numbered from 1 to 20. Krishna selects a card at random from these cards. What is the probability that this card selected at random is a multiple of 3?

The correct option is D 310 The multiples of 3 from 1 to 20 are : 3, 6, 9, 12, 15, and 18. It can be seen that there are 6 multiples. Number of favourable outcomes = 6 Total number of outcomes = Total number of cards = 20 Hence P(selecting a card divisible by 3) = 620 = 310