Question

There are $2n$ things out of which ${}^{\prime }{n}^{\prime }$ are alike and ${}^{\prime }{n}^{\prime }$ are different, the number of ways of selecting ${}^{\prime }{n}^{\prime }$ things is :-

• A. ${}^{2n}{C}_n$
• B. $2^n-1$
• C. $2^n$
• D. $n$

Answer 1

The correct option is A ${}^{2n}{C}_n$

No. of ways to select things out of $2n={}^{2n}{C}_n$

Hence, the answer is ${}^{2n}{C}_n.$