There are 3 copies each of 4 different books. In how many ways can they be arranged in a shelf?

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Solution

$\frac{12!}{(3!)^{4}}$ since there are 4 sets of 3 alike books.

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There are 3 copies each of 4 different books. In how many ways can they be arranged in a shelf?

12!(3!)4 since there are 4 sets of 3 alike books.

$\frac{12!}{(3!)^{4}}$ since there are 4 sets of 3 alike books.