3menand2womencommitteeoftwoformedwith1manand1womanis=3C1×2C1=3×2=6twocommitteeisformed⇒(either0manoutof3)×(2womenoutof2women)=3C0×2C2=1⇒(1manoutof3)×(1womenoutof2women)=3C1×2C1=3×2=6⇒(2manoutof3)×(0womenoutof2women)=3C2×2C0=3×1=3Thenprobabilityofgrampanchayatwithtwocommittee=(3C1×2C1)10=3×210=35