Question

There are $3$ red-colored chalks and $5$ blue-colored chalks. If $8–5=3$ is one of the equations from the fact family of the numbers $3,5,$ and $8,$ what are the remaining three equations that can be formed?

• A. $3+8=5,8+3=5,5–8=3$
• B. $7+1=8,1+7=8,8–1=7$
• C. $8–3=5,3+5=8,5+3=8$
• D. $6+2=8,2+6=8,8–6=2$

Answer 1

The correct option is C $8–3=5,3+5=8,5+3=8$

Say: Let us read the question.

Ask:
$\bullet$ What is the equation to find the total number of chalks?
Ans: $3+5=8$
$\bullet$ How else can you frame the addition equation?
Ans: $5+3=8$
$\bullet$ What is the given subtraction equation?
Ans: $8–5=3$
$\bullet$ What will be the other subtraction equation that can be formed using these $3$ numbers?
Ans: $8–3=5$

Hence, option C is the correct answer.

WB: Use the whiteboard to draw the number frame and write the equations.

Probing Question:
If we subtract $3$ from $8,$ the framed equation will not be a part of the fact family, because the difference will not be 5. Is this true? Why?
A: No, because $8–5=3,$ so if we subtract $3$ from $8$ we will always get $5$ as the difference because $3$ and $5$ together make $8$.