There are 3 white, 4 blue and 1 red flowers, All of them are taken out one by one and arranged in a row in the order.How many different arrangements are possible (flowers of same colours are similar)?.

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Solution

We have,
Total no. of different arrangements $\frac{8!}{3! 4!}$
$= \frac{8 \times 7 \times 6 \times 5}{6} = 280$

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There are 3 white, 4 blue and 1 red flowers, All of them are taken out one by one and arranged in a row in the order.How many different arrangements are possible (flowers of same colours are similar)?.

We have,Total no. of different arrangements 8!3!4!=8×7×6×56=280

We have,
Total no. of different arrangements $\frac{8!}{3! 4!}$
$= \frac{8 \times 7 \times 6 \times 5}{6} = 280$