There are 39 milkcakes and 26 pedas in 2 individual baskets. What is the largest group into which both the sweets can be split so that they can be equally arranged in some other individual baskets?

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Solution

The correct option is A 13
The largest group into which both sweets can be split will be the HCF of the number of sweets of both type, i.e. 39 and 26.

Factors of 39: 1, 3, 13, 39
Factors of 26: 1, 2, 13, 26
Common factors: 1, 13
HCF of 39 and 26 = 13

Thus, the largest group size will be 13 sweets in each basket.

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There are 39 milkcakes and 26 pedas in 2 individual baskets. What is the largest group into which both the sweets can be split so that they can be equally arranged in some other individual baskets?​

There are 39 milkcakes and 26 pedas in 2 individual baskets. What is the largest group into which both the sweets can be split so that they can be equally arranged in some other individual baskets?