There are 4 defective items in a lot consisting of 10 items. From this lot we select 5 items at random. The probability that there will be 2 defective items among them is?
A
12
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B
25
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C
521
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D
1021
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Solution
The correct option is D1021 number of defective items =4
Total number of items =10
number of ways to select 5 items =10C5=10!5!(10−5)!=252
number of ways in which 2 defective systems and 3 non defective are selected