Question

There are $4$ numbers. The HCF of each pair is $7$ and the LCM of all the numbers is $1470$. What is the product of the 4 numbers?

• A. $504210$
• B. $502410$
• C. $504120$
• D. $501420$

Answer 1

The correct option is A $504210$

Since the HCF of each pair = 7
let the four numbers be 7a, 7b, 7c, 7d
Also LCM = abcd x HCF
$e\Rightarrow abcd=\frac{1470}{7}=210$
$\therefore Productofthenumbers=7a\times 7b\times 7c\times 7d=7^4\times abcd=7^4\times 210=504210$