There are $40$ tickets numbered from $1 - 40$ , one ticket is drawn at random. Find the probability of getting $(a)$ divisible of $4$ and $(b)$ prime numbers.

Open in App

Solution

numbers divisible by 4 in 1 - 40 are
4, 8, 12, 16, 20, 24, 28, 32, 36, 40
P (divisible by 4) $= \frac{10}{40} = \frac{1}{4} = 0.25$
Prime numbers in 1 - 40 are
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37,
P ( prime numbers) = $\frac{12}{40} = \frac{3}{10} = 0.3$

Suggest Corrections

Similar questions

Q. From

21

tickets numbered

1, 2, 3, . . . . . . . ., 21

one ticket is drawn at random. Find the probability that the ticket has a number divisible by

3

One lottery ticket is drawn at random from a bag containing

20

tickets numbered from

1

20

. Find the probability that the number drawn is divisible by

3

5

Q. A bag contains tickets numbered from 1 to 20. Two tickets are drawn. Find the probability that (i) both the tickets have prime numbers on them (ii) on one there is a prime number and on the other there is a multiple of 4.

Q. A ticket is drawn at random from a bag containing tickets numbered from 1 to 40. Find the probability that the selected ticket has a number which is multiple of 5.

One ticket is drawn at random from a bag containing tickets numbered 1 to 40. The probability that the selected ticket has a number, which is a multiple of 7, is
(a) $\frac{1}{7}$ (b) $\frac{1}{8}$ (c) $\frac{1}{5}$ (d) $\frac{7}{40}$

Join BYJU'S Learning Program

There are 40 tickets numbered from 1−40, one ticket is drawn at random. Find the probability of getting (a) divisible of 4 and (b) prime numbers.

numbers divisible by 4 in 1 - 40 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40P (divisible by 4) =1040=14=0.25Prime numbers in 1 - 40 are2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37,P ( prime numbers) = 1240=310=0.3

There are $40$ tickets numbered from $1 - 40$ , one ticket is drawn at random. Find the probability of getting $(a)$ divisible of $4$ and $(b)$ prime numbers.

numbers divisible by 4 in 1 - 40 are
4, 8, 12, 16, 20, 24, 28, 32, 36, 40
P (divisible by 4) $= \frac{10}{40} = \frac{1}{4} = 0.25$
Prime numbers in 1 - 40 are
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37,
P ( prime numbers) = $\frac{12}{40} = \frac{3}{10} = 0.3$