Question

There are 48 cricket balls, 72 hockey balls and 84 tennis balls and they have to be arranged in several rows in such a way that every row contains the same number balls of one type. What is the minimum number of rows required for this to happen?

• A. 12
• B. 16
• C. 17
• D. 19
• E. None of these

Answer 1

The correct option is C 17

HCF of 48, 72 and 84 = $2^2\times 3=12$
The minimum number of rows $=\frac{48}{12}+\frac{72}{12}+\frac{84}{12}$
= 4 + 6 + 7 = 17