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Question

There are 5 blue cars and twice as many red cars than blue cars on the road.
There are __ red cars.
Identify the addition and subtraction equations.

A
5;5+5=10,5+5=10;105=5,510=5
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B
15;155=10,1510=5;5+10=15;10+5=15
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C
10;10+5=15,5+10=15,155=10;1510=5
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D
10;5+5=10,5+5=10;105=5,510=5
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Solution

The correct option is C 10;10+5=15,5+10=15,155=10;1510=5
Say: Let's read the question.

Ask:
What do we have to do here?
Ans: We need to identify the number of red cars, and then identify the related addition and subtraction equations for the total number of cars on the road.

Say: Let us begin by finding the number of red cars.

Ask:
How many blue cars are there?
Ans: 5
How many red cars are there?
Ans: Twice as many as the blue cars.
How much is twice as much as 5?
Ans: 10
How did we find this?
Ans: By adding 5 two times, i.e., 5+5=10
So, how many red cars are there?
Ans: 10
Say: Now let us identify the related addition and subtraction equations for the total number of cars on the road.

Ask:
How many blue cars are there?
Ans: 5
How many red cars are there?
Ans: 10
What are the two addition equations that can be framed to find the total number of cars?
Ans: 10+5=15 and 5+10=15
How do we find the difference?
Ans: By subtracting the smaller number from the bigger number.
Using the same three numbers, i.e., 5,10, and 15, what subtraction equation can be framed?
Ans: 155=10 and 1510=5

Hence, Option B is correct.

WB: If required, use the whiteboard to represent the bigger number and check the smaller number as shown, and write the related addition and subtraction equations.

Probing Question:
Q. So, what are the related addition and subtraction equations that are framed?
A. Addition equations: 10+5=15 and 5+10=15
Subtraction equations: 155=10 and 1510=5


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