The correct option is B 15000
The required number of distribution = Total number of distribution - Number of distribution in which ball 2 and ball 4 are together.
Here the total number of distributions = 16800.
Now, consider ball 2 and ball 4 are stuck together and this arrangement is assumed to be a single ball.
Thus we have 6 balls to be distributed into 5 boxes.Which can be done as 1, 1, 1, 1, 2 in 5C1×6C2×4! ways=1800.
5C1→ Number of ways of selecting one box in which two balls are kept together.
6C2→ Number of ways of selecting 2 balls out of 6 balls.
4!→ Number of ways of distribution of remaining 4 balls in remaining 4 boxes.
Hence, the required number of ways = 16800 - 1800 = 15000