There are 50 turns of a wire in every 1cm length of a long solenoid. If a 4A current is flowing in the solenoid, the approximate value of magnetic field along its axis at an internal point and at one end will be respectively
A
12.6×10−3Weberm2,6.3×10−3Weberm2
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B
12.6×10−3Weberm2,25.1×10−3Weberm2
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C
25.1×10−3Weberm2,12.6×10−3Weberm2
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D
25.1×10−5Weberm2,6.3×10−5Weberm2
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Solution
The correct option is C25.1×10−3Weberm2,12.6×10−3Weberm2 No of turns per metre =500.01=5000 Magnetic field inside the solenoid is given by Bin=μ0ni
and magnetic field at the ends of a solenoid is given by Bend=Bin2=μ0ni2
Substituting the values of μ0=4π×10−7,i=4A and n=5000, we get Bin=25.1×10−3Weberm2 and Bend=12.6×10−3Weberm2