There are 6 friends A,B,C,D,E and F. B does not want to sit next to D,E or F and E does not want to sit next to A,B or C. In how many ways can you arrange these 6 people around a circular table?
If B, does not want any neighbour among D,E,F, B needs to be seated between only A and C. A and C can be arranged in 2! Ways
Similarly, E who does not want to be seated next to A,B or C will be seated between the other two( D,F). Those two can be arranged in 2! Ways.
Total number of arrangements= 2*2= 4