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Question

There are 6 friends A,B,C,D,E and F. B does not want to sit next to D,E or F and E does not want to sit next to A,B or C. In how many ways can you arrange these 6 people around a circular table?

A
8
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B
2
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C
1
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D
4
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E
3
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Solution

The correct option is D 4

If B, does not want any neighbour among D,E,F, B needs to be seated between only A and C. A and C can be arranged in 2! Ways

Similarly, E who does not want to be seated next to A,B or C will be seated between the other two( D,F). Those two can be arranged in 2! Ways.

Total number of arrangements= 2*2= 4


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