The correct option is
A 36There are 6 letters and 3 post boxes
Lets consider letter 1,2,3,4,5,6 as L1,L2,L3,L4,L5,L6respectively.
Also post boxes 1,2,3 as P1,P2,P3 respectively
Now L1 could be placed in any of P1,P2,P3. Thus, there are 3 ways to post L1
Hence, there are 3×3×3×3×3×3 =36 ways to post 6 letters in 3 post boxes.