Question

There are 6 red and 5 black balls in a bag. A ball is drawn from the bag at random and without replacing it an other ball is drawn at random. The probability that both the balls drawn may be red is

• A. $\frac{2}{11}$
• B. $\frac{3}{11}$
• C. $\frac{6}{11}$
• D. $\frac{5}{11}$

Answer 1

Answer: (B)

$\frac{3}{11}$

A bag contains: $6R+5B=11$
Probability of getting $1R+1R$ ball from this bag without replacement:
$=\left(\frac{6}{11}\right)\times \left(\frac{5}{10}\right)=\frac{3}{11}$