There are $6$ red balls and $6$ green balls in a bag. Find the probability of picking a red ball.

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Solution

No .of red balls are $= 6$

No .of green balls are $= 6$

No .of total balls is $6 + 6 = 12$

Probability of picking red ball is $\frac{6}{12} = \frac{1}{2}$

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There are 6 red balls and 6 green balls in a bag. Find the probability of picking a red ball.

No .of red balls are =6No .of green balls are =6No .of total balls is 6+6=12Probability of picking red ball is 612=12

There are $6$ red balls and $6$ green balls in a bag. Find the probability of picking a red ball.

No .of red balls are $= 6$

No .of green balls are $= 6$

No .of total balls is $6 + 6 = 12$

Probability of picking red ball is $\frac{6}{12} = \frac{1}{2}$