There are 7 chocolates be distributed among 10 children subject to condition that child can take any number of chocolates. Find the required number of ways to do this if chocolates are identical.

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Solution

The correct option is D

Let the persons be $A_{1}, A_{2}, A_{3}, . . . . . . . . . A_{10}$

Now, distribute 7 chocolates among 10 people

$A_{1} + A_{2} + A_{3} + . . . . . . . . . A_{10}$ = 7

Number of ways = $^{7 + 10 - 1} C_{10 - 1}$ = $^{16} C_{9}$ = $^{16} C_{7}$

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There are 7 chocolates be distributed among 10 children subject to condition that child can take any number of chocolates. Find the required number of ways to do this if chocolates are identical.

The correct option is D Let the persons be A1,A2,A3,.........A10 Now, distribute 7 chocolates among 10 people A1+A2+A3+.........A10 = 7 Number of ways = 7+10−1C10−1 = 16C9 = 16C7

The correct option is D

Let the persons be $A_{1}, A_{2}, A_{3}, . . . . . . . . . A_{10}$

Now, distribute 7 chocolates among 10 people

$A_{1} + A_{2} + A_{3} + . . . . . . . . . A_{10}$ = 7

Number of ways = $^{7 + 10 - 1} C_{10 - 1}$ = $^{16} C_{9}$ = $^{16} C_{7}$