The correct option is D 15120
There are 6 subjects and 7 periods. Each subject is allowed atleast one period.
Therefore, two periods will have the same subject and the remaining five periods will have different subjects.
Two periods can be selected from 7 periods that have the same subject in 7C2 ways.
Subject (same) allocated to these two periods can be selected in 6C1 ways.
Now, we are left with five subjects and five periods. Remaining 5 subjects can be arranged in the remaining 5 periods in 5! ways.
Required number of ways
= 7C2× 6C1×5!
=21×6×120
=15120
Therefore, option (d.) is the correct answer.