Question

There are $7$ red disks and $5$ yellow disks in bag $X$ and there are $5$ red disks and $15$ yellow disks in bag $Y$. If one disk is selected at random from each bag, find the probability that both disks selected are yellow.

• A. $\frac{5}{48}$
• B. $\frac{7}{48}$
• C. $\frac{1}{16}$
• D. $\frac{7}{16}$
• E. $\frac{3}{4}$

Answer 1

Answer: (C)

$\frac{1}{16}$

Given, $7$ red disks and $5$ yellow in box $x$ and $5$ red disks and $15$ yellow disks in $y$ bag.

Then total balls in both bags $=7+5+5+15=32$ balls

If one yellow ball selected at random the balls $=1+1=2$

Then probability both disks selected $=$ $\frac{2}{32}=\frac{1}{16}$